Backend Engineering
Senior
programming
LeetCode #1480 - Running Sum of 1d Array
Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]). Return the running sum of nums.
Example
#### Input
nums = [1,2,3,4]
#### Output
[1,3,6,10]
Constraints
1 <= nums.length <= 1000
-10^6 <= nums[i] <= 10^6
```
## Approach
We will iterate through the array and maintain a cumulative sum as we go. This will allow us to build the running sum in linear time.
## Complexity
**Time:** O(n)
**Space:** O(1)
## Trade-offs
- This approach is efficient and straightforward but requires extra space for the output array.
```
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